"A steam turbine operates at steady state with inlet conditions of 4 MPa, 400°C, and velocity 50 m/s. Exit is 100 kPa, quality 90%, velocity 100 m/s. Find power output per kg of steam."
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h2 = hf + x hfg at 100 kPa = 417.5 + 0.9 2257.5 = 417.5 + 2031.75 = 2449.25 kJ/kg. Then W = (3214.5 – 2449.25) + (50^2 – 100^2)/2000 = 765.25 + (2500 – 10000)/2000 = 765.25 + (-7500/2000) = 765.25 – 3.75 = 761.5 kJ/kg.